Hydrostatic pressure (P) under a water depth of h can be given as P = h \rho g , where \rho is water density at normal temperature and pressure, while g is acceleration due to gravity.

Water pressure P = 270 kPa

Converting Kilopascal to Pascal we get P = 270000 Pa = 270000 \frac{kg}{m \cdot s^{2}}

Plugging this in P = h\rho g and solving for h we get,

h = \frac{P}{\rho g}

= \frac{270000 \frac{kg}{m\cdot s^{2}}}{(1000 \frac{kg}{m^{3}})(9.81\frac{m}{s^{2}})}**= 27.51 m **

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